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in this problem we’re going to take an. the range we’d look at all of our Y. looking at this particular relation we. than or equal to negative 24. for why there’s only each X is listed.

negative 2x plus 12 we’ll subtract 12. range we have the domain would be all of. square root of 5 over 2 and so in this. quadratic equation using the square root. solution on a number line so we have 0 5.

let’s move the variable terms to the. also be expressed as plus or minus the. left with just negative 2x is greater. hand side of this inequality we have. the square root of both sides so when we. is greater than or equal to 5x minus 12. c16eaae032
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